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The Dallas Cowboys kicked off its 2019 training camp in Oxnard, California this past weekend, but it was without key member and star running back Ezekiel Elliott. Elliott made the decision to holdout from training camp as he wants a new deal with two years left remaining on his rookie contract.
As Dallas installs new wrinkles into its offense with Kellen Moore in charge, the team went out and inked a familiar face: veteran Alfred Morris. Ian Rapoport broke the news over Twitter:
Reunion: Free agent RB Alfred Morris has agreed to terms with the #Cowboys, per his agents the Katz Bros. He averaged almost 5 yards per carry for them two years ago.
— Ian Rapoport (@RapSheet) July 30, 2019
Morris was most recently on the Dallas Cowboys during the 2017 campaign when he backed up Elliott. He spent two years in Dallas and started five games, totaling 790 yards and three touchdowns on the ground. Morris, of course, also starred with divisional foe Washington alongside Robert Griffin III.
The veteran back spent last season in San Francisco with the 49ers, rushing for 428 yards and a pair of scores. The Cowboys need depth at the running back position and maybe a little veteran leadership, so they went out and inked a deal with Morris.
UPDATE: Jane Slater of NFL Network has reported that Alfred Morris will be with the team in Oxnard tomorrow. Morris worked out with the New Orleans Saints on Monday, but feels that Dallas is home.
The Katz brothers, his agents, tell me he will be in Oxnard for training camp Tuesday. He worked out for the #Saints today but when #Cowboys called it was an easy pick. He feels like Dallas is home. It’s where his wife, 2 kids and his newborn have remained when he was in SF. https://t.co/fEHChbnIED
— Jane Slater (@SlaterNFL) July 30, 2019